code:

//Need these for printWriter, parseLong, etc:
import java.lang.*;
import java.io.*;


public class problem1{ //note that we have to allow the exception below
	public static void main(String[] args) {
		//initialize variables
		long a = 1;
		long b = 1;
		long c = 1;
		long d = 1;
		long e = 1;

        long maxLimit = 10000000;

		for (; a <= maxLimit; a++){
			if (expSum(a,b,c,d) == exp(e))
				break;
			for (; b <= maxLimit; b++){
				if (expSum(a,b,c,d) == exp(e))
					break;
				for (; c <= maxLimit; c++){
					if (expSum(a,b,c,d) == exp(e))
						break;
					for (;  d <= maxLimit; d++){
						if (expSum(a,b,c,d) == exp(e))
							break;
						for (; e <= maxLimit; e++){
							if (expSum(a, b, c, d) == exp(e))
								break;
						}
					}
				}
			}
		}

	//NOTE TO SELF: MAKE SURE TO CHANGE THIS PRINT STATEMENT TO OUTPUT TO FILE
	//BEFORE TURNING IN PROGRAM! (KEEP SIMPLE FOR DEBUGGING RIGHT NOW)
	System.out.println("WIBBLY WOBBLY. TIMEY WIMEY. WE HAVE A SOLUTION.");
	System.out.println("PROBABLY COULD BE MORE EFFICIENT.");
	System.out.println("BUT DOWN THAT ROAD LIES ONLY SORROW AND RAGE");
	System.out.printf("A: %d\tB: %d\tC: %d\tD: %d\tE: %d", a, b, c, d, e);
	System.out.println("HEY! GREG! DID YOU REMEBER TO CHANGE THIS TO OUTPUT TO A FILE? OBVIOUSLY NOT!");
	}
	// returns the value of a numbr to the power of 6
	public static long exp(long number){
		long exponent = number * number * number * number * number;
		return exponent;
	}

	//computes sum of a^5 + b^5 + c^5 + d^5...
	//not _technically_ nessecary, but sure helps readability!
	public static long expSum(long a, long b, long c, long d)
	{
		long sum = exp(a) + exp(b) + exp(c) + exp(d);
		return sum;
	}
}