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Rob Filter
Jan 19, 2009

GaussianCopula posted:

Well the real math is pretty easy. Given that our goal is to eliminate as much people as possible with each question and both answers (yes/no) are equally desirable (e.g. you dont get another turn if the answer is yes) then we can model it as:

x is the % of people that fit the question, has to be in the intervall ]0;1[

That means that the average number of eliminated candidates can be expressed as

x*(1-x)+(1-x)*x
which is the same as 2x-2x^2 which is a parabola with a maximum at 0.5.

Not exactly. Consider:

Your opponent only has one choice left. You have twenty. Which lets you win more often;

1. Narrow the field down to 10/10, and immediately lose.
2. Take a 1 in 20 guess.

Your strategy has to take into account opponent boardstate.

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Rob Filter
Jan 19, 2009
I remember during the rebel / traitor game where he grabbed one of the women's face to ask her if she was a rebel or not, violating her personal space.

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